We use cookies to give you the best experience possible. By continuing we’ll assume you’re on board with our cookie policy

See Pricing

What's Your Topic?

Hire a Professional Writer Now

The input space is limited by 250 symbols

What's Your Deadline?

Choose 3 Hours or More.
2/4 steps

How Many Pages?

3/4 steps

Sign Up and See Pricing

"You must agree to out terms of services and privacy policy"
Get Offer

Patterns Portfolio

Hire a Professional Writer Now

The input space is limited by 250 symbols

Deadline:2 days left
"You must agree to out terms of services and privacy policy"
Write my paper

Truong Nguyen
Patterns of Recognition
This portfolio problem ask us to find the number of blocks in certain train patterns. It wants to know how many blocks are in the fourth train? How many blocks are in the eighth train? How can you tell how many blocks will be in a later train in the pattern?
For the diagram number one I got 1 block, for number two I got 5 blocks and for the diagram number three I got 10 blocks. If it went on to the fourth train, there will be 16 boxes.

And there will be 36 blocks in the eighth train.
To find how many blocks are in the first pattern train, I counted it. There was only 1 block in the first pattern. I counted the second pattern and there were 5 more blocks; therefor the second pattern has 6 blocks total. I counted the blocks again in the third pattern to find how many blocks are in it. The third pattern has 5 more blocks added on to the second pattern.

Don't use plagiarized sources. Get Your Custom Essay on
Patterns Portfolio
Just from $13,9/Page
Get custom paper

Therefor, the third pattern has a total of 11 blocks.
I found the equation by observing the first three patterns given. I know that the first part has only 1 block. After the first pattern, there were 5 blocks added on to make the 2nd pattern. After the second pattern, there were 5 more blocks added to make the third pattern. From that observation, I know that there will be 5 more blocks added on each time to make the next pattern. Because the first pattern is different from the other pattern in that it only has 1 block, I wrote 1 in the equation to represent the first pattern. I represented the pattern number with the variable ‘n’. I know that each time the pattern number increases, you add 5 more blocks. But since pattern number one, like I mentioned before, is different I subtract it from the ‘n’. Next I multiply the ‘n-1’ by five (the number of blocks added on more each time). However, just because the pattern one is different doesn’t mean we disregard it because pattern one has one block. So I added 1 to [5x(n-1)].
Now my equation is 1 + 5(n-1)..

Cite this Patterns Portfolio

Patterns Portfolio. (2018, Aug 25). Retrieved from https://graduateway.com/patterns-portfolio/

Show less
  • Use multiple resourses when assembling your essay
  • Get help form professional writers when not sure you can do it yourself
  • Use Plagiarism Checker to double check your essay
  • Do not copy and paste free to download essays
Get plagiarism free essay

Search for essay samples now

Haven't found the Essay You Want?

Get my paper now

For Only $13.90/page