The intent of this lab was to:
* Determine the heat of neutralisation for the reaction of Na hydrated oxide ( NaOH ) and hydrochloric acid ( HCI ) .
The heat of neutralisation ( ?Hneutzn ) is the heat transferred when 1 mol of an acerb reacts with 1 mol of a base. This heat is by and large reported in either kilojoules per mole ( kJ/mol ) or Calories per mole ( kcal mol ) . The reaction of HCI and NaOH solutions is shown in Equation 1.
HCI ( aq ) + NaOH ( aq ) H20 ( cubic decimeter ) + NaCI ( aq ) ( Eq. 1 )
The heat of neutralisation for a reaction can non be measured straight. However. the heat transferred during a neutralization reaction can be calculated from research lab informations.
Glassware: ( 2 ) 150-mL beaker. graduated cylinder. glass rod. ( 2 ) thermometer Equipment: Ring base. dual thermometer clinch. polystyrene cup Chemicals: 2M hydrochloric acid. 2M Na hydrated oxide.
In this experiment. you will find the temperature alteration ( ?T ) for a neutralisation reaction as follows.
In the research lab. you will mensurate time-temperature informations at alternate 30-s intervals over a 5-min period for measured volumes of NaOH solution and of HCI solution. After you mix the two solutions. you will roll up time-temperature informations at 5. 5 min and so at 1-min intervals over a 15-min period for the mixture. From time-temperature graphs of these informations. you will happen AT. You will plot the temperature in grades Celsius on the ordinate ( y-axis ) . You will plot the clip in proceedingss on the abscissa ( x-axis ) . Use of an interrupted temperature axis is a convenient manner to plot such informations.
After the information is plotted. you will pull a perpendicular line. perpendicular to the x-axis through the point on the x-axis that represents the clip of blending. Next you will pull the best consecutive line through the aforethought points for the temperature of each of the reactants. You will generalize these lines so they intersect the line of blending. The points where these lines intersect the line of blending are the initial temperatures of the reactants. To cipher the temperature alteration. you will average the two initial temperatures of the reactants and usage that value as the initial temperature ( Tinitial ) of the reactants. You will so pull the best consecutive line stand foring the aforethought points for the temperature of the reaction mixture. Widen this line to cross the line of blending. This intersection point is the concluding temperature ( Tfinal ) of the reaction mixture.
You will find ?T for the reaction by deducting the initial temperature from the concluding temperature. From ?T and the volumes and molar concentrations of the reactants. along with some literature informations. you will cipher ?Hneutzn in kj/mol for the reaction of HCI solution and NaOH solution
Observation/ CalculationsSee affiliated Sheets
We observed the heat of neutralisation for the reaction of Na hydrated oxide ( NaOH ) and hydrochloric acid ( HCI ) . Heat is transferred from the system ( the reaction mixture ) to the environment in this reaction. Because the heat is lost from the system. the heat alteration of the system is negative. Therefore. this ?Hneutralization should be negative. Therefore a subtraction mark must be topographic points in forepart of the deliberate consequences kilojoules. And can be better calculated in a more insulated system.